{"id":17961,"date":"2024-03-05T06:46:53","date_gmt":"2024-03-05T06:46:53","guid":{"rendered":"https:\/\/soicau5096.minhngocxoso.com\/?p=17961"},"modified":"2024-03-05T06:46:53","modified_gmt":"2024-03-05T06:46:53","slug":"chia-se-du-doan-cau-lo-chinh-xac-100","status":"publish","type":"post","link":"https:\/\/lotoxs.com\/chia-se-du-doan-cau-lo-chinh-xac-100\/","title":{"rendered":"chia s\u1ebb d\u1ef1 \u0111o\u00e1n c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100%"},"content":{"rendered":"
<\/p>\n\n\n
Soi c\u1ea7u ch\u00ednh x\u00e1c nh\u1ea5t l\u00e0 m\u1ed9t trong nh\u1eefng kh\u00e1i ni\u1ec7m r\u1ea5t \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi quan t\u00e2m. \u0110\u1ed1i v\u1edbi nh\u1eefng ng\u01b0\u1eddi hay c\u00e1 c\u01b0\u1ee3c th\u00ec kh\u00e1i ni\u1ec7m n\u00e0y kh\u00f4ng c\u00f2n xa l\u1ea1 g\u00ec n\u1eefa. Nh\u01b0ng v\u1edbi m\u1ed9t s\u1ed1 ng\u01b0\u1eddi th\u00ec c\u00f3 l\u1ebd n\u00f3 ho\u00e0n to\u00e0n m\u1edbi m\u1ebb, v\u1eady soi c\u1ea7u ch\u00ednh x\u00e1c nh\u1ea5t l\u00e0 g\u00ec, ch\u00fang ta c\u00f9ng t\u00ecm hi\u1ec3u n\u00e0o v\u00e0 c\u00f9ng l\u1ea5y cho m\u00ecnh b\u1ea1ch th\u1ee7 l\u00f4, song th\u1ee7 l\u00f4\u2026<\/p>\n\n\n\n
Soi c\u1ea7u ch\u00ednh x\u00e1c nh\u1ea5t l\u00e0 h\u00ecnh th\u1ee9c m\u00e0 b\u1ea1n d\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u1ee7a c\u00e1c mi\u1ec1n nh\u1eb1m \u0111\u1ec3 ch\u1ecdn ra nh\u1eefng con l\u00f4 (con \u0111\u1ec1) hay nh\u1ea5t m\u00e0 b\u1ea1n c\u1ea3m nh\u1eadn r\u1eb1ng n\u00f3 s\u1ebd v\u1ec1 trong k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m nay.<\/p>\n\n\n\n
\u00dd ngh\u0129a c\u1ee7a c\u1ea7u l\u00e0 g\u00ec? C\u1ea7u l\u00e0 t\u1eadp h\u1ee3p c\u00e1c c\u1eb7p s\u1ed1 \u0111\u01b0\u1ee3c gh\u00e9p t\u1eeb d\u00e3y s\u1ed1 t\u1eeb 0 \u0111\u1ebfn 9 theo m\u1ed9t quy lu\u1eadt c\u00f3 s\u1eb5n trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 (xsmb, xsmn).<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c tuy\u1ec7t \u0111\u1ed1i n\u00e0y l\u00e0 l\u1ea5y k\u1ebft qu\u1ea3 s\u1ed1 \u0111\u1ec1 c\u1ee7a 2 ng\u00e0y h\u00f4m tr\u01b0\u1edbc x\u1ebfp th\u00e0nh h\u00e0ng d\u1ecdc, r\u1ed3i c\u1ed9ng l\u1ea7n l\u01b0\u1ee3t t\u1eebng ch\u1ed7 s\u1ed1 theo h\u00e0ng d\u1ecdc \u0111\u1ec3 t\u00ednh ra k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m sau (\u0111i\u1ec1u ki\u1ec7n k\u1ebft qu\u1ea3 ph\u1ea3i b\u1eb1ng 10 ho\u1eb7c 20).<\/p>\n\n\n\n
\u0110\u1ec1 v\u1ec1 ng\u00e0y 1 g\u1ecdi l\u00e0 AB th\u00ec: A + B + X = 10 (ho\u1eb7c 20) => X = 10 (ho\u1eb7c 20) \u2013 A \u2013 B<\/p>\n\n\n\n
\u0110\u1ec1 v\u1ec1 ng\u00e0y 2 g\u1ecdi l\u00e0 CD th\u00ec: C + D + Y = 10 (ho\u1eb7c 20) => Y = 10 (ho\u1eb7c 20) \u2013 C \u2013 D<\/p>\n\n\n\n
Soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% v\u00e0o ng\u00e0y 3: \u0110\u00e1nh l\u00f4 XY.<\/p>\n\n\n\n
\u0110\u1ec3 c\u00e1c b\u1ea1n hi\u1ec3u r\u00f5 c\u00e1ch t\u00ednh c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 n\u00e0y h\u01a1n, soicauchinhxacnhat.com<\/strong> s\u1ebd l\u1ea5y v\u00ed d\u1ee5 th\u1ef1c t\u1ebf v\u00e0o \u0111\u1ea7u n\u0103m 2024 c\u1ee7a k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc cho c\u00e1c b\u1ea1n d\u1ec5 t\u00ednh nh\u00e9.<\/p>\n\n\n\n Th\u01b0\u1eddng th\u00ec khi v\u1ec1, c\u1ea7u n\u00e0y s\u1ebd v\u1ec1 li\u00ean t\u1ee5c 3 \u0111\u1ebfn 4 ng\u00e0y, \u0111\u00e3 \u0111\u01b0\u1ee3c ki\u1ec3m ch\u1ee9ng. \u0110\u00e2y l\u00e0 v\u00ed d\u1ee5 th\u1ef1c t\u1ebf trong th\u00e1ng 1\/2024 m\u00e0 m\u00ecnh \u0111\u00e3 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100%, m\u1eddi c\u00e1c anh em c\u00f9ng xem b\u00ean d\u01b0\u1edbi:<\/p>\n\n\n\n Ng\u00e0y 1\/1 \u0110\u1ec1 ra con 51 X = 10 \u2013 5 \u2013 1 = 4<\/p>\n\n\n\n Y = 10 \u2013 0 \u2013 3 = 7<\/p>\n\n\n\n Ng\u00e0y 3\/1 soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% l\u00e0 ph\u1ea3i \u0111\u00e1nh l\u00f4 47 => L\u00f4 v\u1ec1 47 \u0111\u00e3 Tr\u00fang r\u1ed3i. Ng\u00e0y 2\/1 \u0110\u1ec1 ra con 03 X = 10 \u2013 0 \u2013 3 = 7<\/p>\n\n\n\n Y = 20 \u2013 8 \u2013 5 = 7<\/p>\n\n\n\n Ng\u00e0y 4\/1 soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% l\u00e0 ph\u1ea3i \u0111\u00e1nh l\u00f4 77 => L\u00f4 v\u1ec1 77 \u0102n ti\u1ebfp t\u1ee5c. Ng\u00e0y 3\/1 \u0110\u1ec1 ra con 85 X = 20 \u2013 8 \u2013 5 = 7<\/p>\n\n\n\n Y = 20 \u2013 9 \u2013 6 = 5<\/p>\n\n\n\n Ng\u00e0y 5\/1 soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% l\u00e0 ph\u1ea3i \u0111\u00e1nh l\u00f4 75 => L\u00f4 ra 75 Ti\u1ebfp t\u1ee5c Tr\u00fang. Ng\u00e0y 6\/1: Soi c\u1ea7u l\u00f4 ra 59 => \u0110\u00e1nh l\u00f4 59 Kh\u00f4ng tr\u00fang C\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% n\u00e0y qu\u1ea3 th\u1ef1c l\u00e0 c\u00f3 k\u1ebft qu\u1ea3 c\u00e1c anh em nh\u00e9. Theo d\u00f5i website \u0111\u1ec3 c\u1eadp nh\u1eadp th\u00eam nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p m\u1edbi nh\u00e9. Ch\u00fac c\u00e1c b\u1ea1n may m\u1eafn<\/p>\n\n\n <\/p>\r\nPh\u1ea3i bi\u1ebft khi n\u00e0o n\u00ean soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c<\/h3>\n\n\n\n
N\u1ebfu c\u00f3 t\u1ea1ch h\u00f4m nay, h\u00f4m sau h\u00e3y ngh\u1ec9, h\u00f4m k\u1ebf ti\u1ebfp m\u00e0 c\u1ea7u l\u00f4 v\u1ec1 th\u00ec ng\u00e0y k\u1ebf ti\u1ebfp n\u1eefa ph\u1ea3i ti\u1ebfp t\u1ee5c ngh\u1ec9 kh\u00f4ng \u0111\u01b0\u1ee3c theo c\u1ea7u. C\u00f2n h\u00f4m k\u1ebf n\u1eefa m\u00e0 ra th\u00ec theo c\u1ea7u.<\/p>\n\n\n\n
Khi c\u1ea7u kh\u00f4ng ra t\u1ea7m 5 ng\u00e0y, ng\u00e0y th\u1ee9 6 h\u00e3y theo c\u1ea7u, n\u1ebfu c\u1ea7u kh\u00f4ng ra th\u00ec ngh\u1ec9 1 h\u00f4m r\u1ed3i \u0111\u00e1nh ti\u1ebfp 3 ng\u00e0y, ho\u1eb7c c\u1ea7u m\u00e0 v\u1ec1 th\u00ec \u0111\u00e1nh ti\u1ebfp ng\u00e0y h\u00f4m sau.
N\u1ebfu soi c\u1ea7u l\u00f4 m\u00e0 c\u1ea7u v\u1ec1 b\u1ecb ng\u01b0\u1ee3c s\u1ed1 (s\u1ed1 b\u1ecb \u0111\u1ea3o), th\u00ec ngh\u1ec9 3, 4 ng\u00e0y sau \u0111\u00f3 theo c\u1ea7u l\u1ea1i.
V\u00ed d\u1ee5 th\u1ef1c t\u1ebf c\u1ee7a c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% trong 01\/2024<\/p>\n\n\n\nTr\u00ean \u0111\u00e2y l\u00e0 h\u01b0\u1edbng d\u1eabn soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% trong th\u1ef1c t\u1ebf<\/h5>\n\n\n\n
Ng\u00e0y 2\/1 \u0110\u1ec1 ra con 03
D\u00f9ng c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% nh\u01b0 tr\u00ean:<\/p>\n\n\n\n
Ti\u1ebfp t\u1ee5c<\/p>\n\n\n\n
Ng\u00e0y 3\/1 \u0110\u1ec1 ra con 85
\u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100%:<\/p>\n\n\n\n
Ti\u1ebfp t\u1ee5c<\/p>\n\n\n\n
Ng\u00e0y 4\/1 \u0110\u1ec1 ra con 96
\u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100%:<\/p>\n\n\n\n
K\u1ebf ti\u1ebfp nh\u1eefng ng\u00e0y d\u01b0\u1edbi t\u00f4i v\u1eabn d\u00f9ng c\u00f4ng th\u1ee9c soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% nh\u01b0 tr\u00ean:<\/p>\n\n\n\n
Ng\u00e0y 7\/1: Ngh\u1ec9
Ng\u00e0y 8\/1: T\u00f4i l\u1ea1i ngh\u1ec9 theo nguy\u00ean t\u1eafc nh\u01b0ng \u00e1p d\u1ee5ng Soi c\u1ea7u l\u00f4 ra 98 v\u1ec1 89. \u0110\u00e2y l\u00e0 L\u00f4 ng\u01b0\u1ee3c. Ngh\u1ec9 ti\u1ebfp 3 \u2013 4 h\u00f4m, ng\u00e0y th\u1ee9 5 ch\u01b0a th\u1ea5y c\u1ea7u v\u1ec1 n\u00ean ng\u00e0y th\u1ee9 6 s\u1ebd ti\u1ebfp t\u1ee5c \u0111\u00e1nh.
Ng\u00e0y 14\/1: Soi c\u1ea7u l\u00f4 ra con 93 => Tr\u00fang.
Ng\u00e0y 15\/1: Soi c\u1ea7u l\u00f4 \u0110\u00e1nh 38 kh\u00f4ng tr\u00fang.
Ng\u00e0y 16\/1: Soi c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 100% ra 83 => Tr\u00fang. Theo quy t\u1eafc, ng\u00e0y n\u00e0y n\u00ean ngh\u1ec9 nh\u01b0ng n\u1ebfu soi c\u1ea7u l\u00f4 m\u00e0 ra th\u00ec ng\u00e0y ti\u1ebfp theo c\u0169ng ph\u1ea3i ngh\u1ec9 th\u00eam v\u00e0i h\u00f4m.<\/p>\n\n\n\n
Ng\u00e0y 17\/1: Ph\u1ea3i ngh\u1ec9 kh\u00f4ng theo c\u1ea7u l\u00f4 n\u1eefa.
Ng\u00e0y 18\/1: Ngh\u1ec9
Ng\u00e0y 19\/1: Theo c\u1ea7u l\u00f4 ch\u00ednh x\u00e1c 51 => Tr\u00fang.
Ng\u00e0y 20\/1: Theo c\u1ea7u l\u00f4 19 ra 91 => Kh\u00f4ng tr\u00fang. N\u00ean ngh\u1ec9 3, 4 h\u00f4m n\u1ebfu ra l\u00f4 ng\u01b0\u1ee3c nh\u01b0 th\u1ebf n\u00e0y.
Ng\u00e0y 25\/1: Theo c\u1ea7u l\u00f4 13 => Tr\u00fang.
Ng\u00e0y 26\/1: Theo c\u1ea7u l\u00f4 35 => Kh\u00f4ng tr\u00fang
Ng\u00e0y 27\/1: Ngh\u1ec9 theo \u0111\u00fang quy t\u1eafc + T\u1ebft Nguy\u00ean \u0110\u00e1n n\u00ean ngh\u1ec9 x\u1ea3 h\u01a1i lu\u00f4n.
=> Trong Th\u00e1ng 1\/2024, nu\u00f4i l\u00f4 11 ng\u00e0y m\u00e0 \u0111\u00e3 c\u00f3 7 ng\u00e0y tr\u00fang. Khi nu\u00f4i b\u1ea1ch th\u1ee7 l\u00f4 m\u00e0 t\u1ec9 l\u1ec7 tr\u00fang cao \u0111\u1ebfn th\u1ebf th\u00ec c\u0169ng \u0111\u00e3 qu\u00e1 qu\u00e1 l\u00e3i.<\/p>\n\n\n\nCH\u1ed0T S\u1ed0 SI\u00caU CHU\u1ea8N V\u00cdP<\/b><\/span><\/h1>\r\n